Thermodynamics Question 3
The pressure in the tyre of a car is four times the atmospheric pressure at 300 K. If this tyre suddenly bursts, its new temperature will be $ T_2 = T_1 \left(\frac{P_2}{P_1}\right)^{(\gamma-1)/\gamma} $ $ (\gamma =1.4) $
[RPMT 1996; MP PMT 1990]
Options:
A) $ \Delta U=0 $
B) $ \Delta U= $ negative value
C) $ \Delta U= $ positive value
D) $ \Delta W= $ zero
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Answer:
Correct Answer: B
Solution:
In case of adiabatic expansion $ \Delta W $ = negative
and $ \Delta Q=0 $ from FLOT $ \Delta Q=\Delta U+\Delta W $
Therefore $ \Delta U=-\Delta W $ i.e., $ \Delta U $ will be negative if work is done on the system.
BETA
