Thermodynamics Question 31
Question: At N.T.P. one mole of diatomic gas is compressed adiabatically to half of its volume$ \gamma =1.41 $ . The work done on gas will be
[RPET 1997]
Options:
A) $ C _{V}(T _{i}-T _{f}) $
B) $ C _{P}(T _{i}-T _{f}) $
C) $ \frac{1}{2}(C _{P}+C _{V})(Ti-T _{f}) $
D) $ (C _{P}-C _{V})(T _{i}-T _{f}) $
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Answer:
Correct Answer: A
Solution:
$ \Delta U=\mu C _{V}\Delta T=1\times C _{V}(T _{f}-T _{i})=-C _{V}(T _{i}-T _{f}) $
Therefore |DU| = CV (Ti - Tf)
BETA
