Thermodynamics Question 121
Question: In thermodynamic process, 200 Joules of heat is given to a gas and 100 Joules of work is also done on it. The change in internal energy of the gas is
[AMU (Engg.) 1999]
Options:
A) 100 J
B) 300 J
C) 419 J
D) 24 J
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta Q=\Delta U+\Delta W $ ;
$ \Delta Q=200J $ and $ \Delta W=-100J $
Therefore $ \Delta U=\Delta Q-\Delta W=200-(-100)=300J $
BETA
