Thermodynamics Question 202
Question: Work done per mol in an isothermal change is
[RPMT 2004; BCECE 2005]
Options:
A) $ RT{\log _{10}}\frac{V _{2}}{V _{1}} $
B) $ RT{\log _{10}}\frac{V _{1}}{V _{2}} $
C) $ RT{\log _{e}}\frac{V _{2}}{V _{1}} $
D) $ RT{\log _{e}}\frac{V _{1}}{V _{2}} $
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Answer:
Correct Answer: C
Solution:
For isothermal process $ PV=RT\Rightarrow P=\frac{RT}{V} $
$ \therefore $ W$ =PdV=\int _{V _{1}}^{V _{2}}{\frac{RT}{V}dV=RT}{\log _{e}}\frac{V _{2}}{V _{1}} $
BETA
