Thermodynamics Question 53
Question: For an adiabatic expansion of a perfect gas, the value of $ \frac{\Delta P}{P} $ is equal to
[CPMT 1983; MP PMT 1990]
Options:
A) $ 1.8\times 10^{5}N/m^{2} $
B) $ 1.5\times 10^{5}N/m^{2} $
C) $ 1.4\times 10^{5}N/m^{2} $
D) $ 1.2\times 10^{5}N/m^{2} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{\text{Adiabatic elasticicity}\ ({E _{\varphi }})}{\text{Isothermal}\ \text{elasticicity}\ ({E _{\theta }})}=\gamma $
Therefore $ {E _{\theta }}=\frac{{E _{\varphi }}}{\gamma } $
Therefore $ {E _{\theta }}=\frac{2.1\times 10^{5}}{1.4} $
$ =1.5\times 10^{5}N/m^{2} $
BETA
