Thermodynamics Question 167
Question: An ideal heat engine working between temperature $ T _{1} $ and $T _{2}$ has an efficiency $ \eta $, the new efficiency if both the source and sink temperature are doubled, will be
[DPMT 2000]
Options:
A) $ \frac{\eta }{2} $
B) $ \eta $
C) $ 2\eta $
D) $ 3\eta $
Show Answer
Answer:
Correct Answer: B
Solution:
In first case $ {\eta _{1}}=\frac{T _{1}-T _{2}}{T _{1}} $ .
In second case $ {\eta _{2}}=\frac{2T _{1}-2T _{2}}{2T _{1}} $
$ =\frac{T _{1}-T _{2}}{T _{1}}=\eta $
BETA
