SATHEE: Thermodynamics Question 178

Thermodynamics Question 178

Question: Work done by 0.1 mole of a gas at $ 27^{o}C $ to double its volume at constant pressure is (R=2 cal mol-C)

[EAMCET 1994]

Options:

A) 54 cal

B) 600 cal

C) 60 cal

D) 546 cal

Show Answer

Answer:

Correct Answer: C

Solution:

$ W=P\Delta V=nR\Delta T=0.1\times 2\times 300=60\ cal $

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Thermodynamics Question 178

Question: Work done by 0.1 mole of a gas at $ 27^{o}C $ to double its volume at constant pressure is (R=2 cal mol-C)

Options:

Answer:

Solution:

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