Thermodynamics Question 25
Question: A given system undergoes a change in which the work done by the system equals the decrease in its internal energy. The system must have undergone an
[Haryana CEE 1996; UPSEAT 2003]
Options:
A) 227.36 K
B) 500.30 K
C) 454.76 K
D) $ -47^{o}C $
Show Answer
Answer:
Correct Answer: A
Solution:
$ T{{V}^{\gamma -1}}= $ constant
Therefore $ \frac{T _{2}}{T _{1}}={{( \frac{V _{2}}{V _{1}} )}^{\gamma }} $
Therefore $ T _{2}=T _{1}{{( \frac{V _{1}}{V _{2}} )}^{\gamma }} $
$ \Rightarrow T _{2}=300{{( \frac{1}{2} )}^{0.4}}=227.36\ K $
BETA
