Thermometry Calorimetry And Thermal Expansion Question 119
Question: A rod of length 20 cm is made of metal. It expands by 0.075cm when its temperature is raised from 0°C to 100°C. Another rod of a different metal B having the same length expands by 0.045 cm for the same change in temperature. A third rod of the same length is composed of two parts, one of metal A and the other of metal B. This rod expands by 0.060 cm for the same change in temperature. The portion made of metal A has the length [CPMT 1991]
Options:
A) 20 cm
B) 10 cm
C) 15 cm
D) 18 cm
Show Answer
Answer:
Correct Answer: B
Solution:
$ \Delta L=L_{0},\alpha \Delta \theta $ Rod A : 0.075 = 20 ´ aA ´ 100 Þ $ {\alpha_{A}}=\frac{75}{2}\times {{10}^{-6}}/{}^\circ C $ rod B : 0.045 = 20 ´ aB ´ 100 Þ $ {\alpha_{B}}=\frac{45}{2}\times {{10}^{-6}}/{}^\circ C $ For composite rod : x cm of A and (20 ? x) cm of B we have 0.060 = x aA ´ 100 + (20 ? x) aB ´ 100 $ =x,[ \frac{75}{2}\times {{10}^{-6}}\times 100+(20-x)\times \frac{45}{2}\times {{10}^{-6}}\times 100 ] $ On solving we get x = 10 cm.
BETA
