Thermometry Calorimetry And Thermal Expansion Question 77
Question: The relative humidity on a day, when partial pressure of water vapour is $ 0.012\times 10^{5},Pa $ at 12°C is (take vapour pressure of water at this temperature as $ 0.016\times 10^{5},Pa $ ) [AIIMS 1998]
Options:
A) 70%
B) 40%
C) 75%
D) 25%
Show Answer
Answer:
Correct Answer: C
Solution:
Partial pressure of water vapour $ P_{W}=0.012\times 10^{5},Pa $ , Vapour pressure of water $ P_{V}=0.016\times 10^{5},Pa $ . The relative humidity at a given temperature is given by $ =\frac{\text{Partial pressure of water vapour}}{\text{Vapour pressure of water}} $ $ =\frac{0.012\times 10^{5}}{0.016\times 10^{5}}=0.75=75% $
BETA
