Transmission Of Heat Question 206
Question: Energy is being emitted from the surface of a black body at $ 127^{o}C $ temperature at the rate of $ 1.0\times 10^{6}J/\sec -m^{2} $ . Temperature of the black body at which the rate of energy emission is $ 16.0\times 10^{6}J/\sec -m^{2} $ will be
[MP PMT 1991; AFMC 1998]
Options:
A) $ 254^{o}C $
B) $ 508^{o}C $
C) $ 527^{o}C $
D) $ 727^{o}C $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{E _{2}}{E _{1}}={{( \frac{T _{2}}{T _{1}} )}^{4}} $
Therefore $ T _{2}={{( \frac{E _{2}}{E _{1}} )}^{1/4}}\times T _{1}={{(16)}^{1/4}}\times (273+127) $
Therefore T2 $ =800\ K=527^{o}C $
BETA
