Transmission Of Heat Question 212
Question: The area of a hole of heat furnace is $ {{10}^{-4}}m^{2} $ . It radiates $ 1.58\times 10^{5} $ calories of heat per hour. If the emissivity of the furnace is 0.80, then its temperature is
Options:
A) 1500 K
B) 2000 K
C) 2500 K
D) 3000 K
Show Answer
Answer:
Correct Answer: C
Solution:
According to Stefen’s law $ E=\sigma ,\varepsilon AT^{4} $
Therefore $ \frac{1.58\times 10^{5}\times 4.2}{60\times 60}=5.6\times {{10}^{-8}}\times {{10}^{-4}}\times 0.8\times T^{4} $
$ T\approx 2500,K $
BETA
