Transmission Of Heat Question 217
Question: The energy emitted per second by a black body at $ 27^{o}C $ is $ 10\ J $ . If the temperature of the black body is increased to $ 327^{o}C $ , the energy emitted per second will be
[CPMT 1999; DCE 1999]
Options:
A) $ 20\ J $
B) $ 40\ J $
C) $ 80\ J $
D) $ 160\ J $
Show Answer
Answer:
Correct Answer: D
Solution:
$ {{(Q)} _{Black,body}}=A\sigma T^{4}t $
Therefore $ Q\propto T^{4} $
Therefore $ Q _{2}=Q _{1}{{( \frac{T _{2}}{T _{1}} )}^{4}} $
$ =10,{{( \frac{273+327}{273+27} )}^{4}} $
$ =10,{{( \frac{600}{300} )}^{4}}=160J $
BETA
