Transmission Of Heat Question 246
Question: If the temperature of the body is increased by 10%, the percentage increase in the emitted radiation will be
[RPMT 2001, 02]
Options:
A) 46%
B) 40%
C) 30%
D) 80%
Show Answer
Answer:
Correct Answer: A
Solution:
$ Q\propto T^{4} $
Therefore $ \frac{Q _{1}}{Q _{2}}={{( \frac{T _{1}}{T _{2}} )}^{4}} $ If $ T _{1}=T $ then $ T _{2}=T+\frac{10}{100}T=1.1T $
Therefore $ \frac{Q _{1}}{Q _{2}}={{( \frac{T}{1.1T} )}^{4}} $
Therefore $ Q _{2}=1.46,Q _{1} $
Therefore % increase in energy $ =\frac{Q _{2}-Q _{1}}{Q _{1}}\times 100=46% $
BETA
