Transmission Of Heat Question 249
Question: Rate of cooling at 600K, if surrounding temperature is 300K is R. The rate of cooling at 900K is
[DPMT 2002]
Options:
A) $ \frac{16}{3}R $
B) $ 2R $
C) $ 3R $
D) $ \frac{2}{3}R $
Show Answer
Answer:
Correct Answer: A
Solution:
Rate of cooling $ \propto (T^{4}-T _{0}^{4}) $
Therefore $ \frac{R _{1}}{R _{2}}=\frac{(T _{1}^{4}-T _{0}^{4})}{(T _{2}^{4}-T _{0}^{4})} $
Therefore $ \frac{R}{R _{2}}=\frac{{{(600)}^{4}}-{{(300)}^{4}}}{{{(900)}^{4}}-{{(300)}^{4}}} $ or $ R _{2}=\frac{16}{3}R $
BETA
