Transmission Of Heat Question 268
Question: The wavelength of maximum energy released during an atomic explosion was $ 2.93\times {{10}^{-10}}m $ . Given that Wein’s constant is $ 2.93\times {{10}^{-3}}m-K $ , the maximum temperature attained must be of the order of
[Haryana CEE 1996; MH CET 2002; Pb. PET 2000]
Options:
A) $ {{10}^{-7}}K $
B) $ 10^{7}K $
C) $ {{10}^{-13}}K $
D) $ 5.86\times 10^{7}K $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \
Therefore \ T=\frac{b}{{\lambda _{m}}}=\frac{2.93\times {{10}^{-3}}}{2.93\times {{10}^{-10}}}=10^{7}\ K $
BETA
