Transmission Of Heat Question 269
Question: The maximum wavelength of radiation emitted at $ 2000\ K $ is $ 4\mu m $ . What will be the maximum wavelength of radiation emitted at
[MP PMT/PET 1998; DPMT 2000]
Options:
A) $ 3.33\ \mu m $
B) $ 0.66\ \mu m $
C) $ 1\ \mu m $
D) $ 1\ m $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \
Therefore $ $ \frac{{\lambda _{m _{2}}}}{{\lambda _{m _{1}}}}=\frac{T _{1}}{T _{2}} $
$ \Rightarrow {\lambda _{m _{2}}}=\frac{2000}{2400}\times 4=3.33\ \mu m $
BETA
