Transmission Of Heat Question 276
Question: The absolute temperatures of two black bodies are 2000 K and 3000 K respectively. The ratio of wavelengths corresponding to maximum emission of radiation by them will be
[RPMT 2003]
Options:
A) 2 : 3
B) 3 : 2
C) 9 : 4
D) 4 : 9
Show Answer
Answer:
Correct Answer: B
Solution:
$ {\lambda _{m}}T={{{\lambda }’} _{m}}{T}’ $
Therefore $ \frac{{\lambda _{m}}}{{{{{\lambda }’}} _{m}}}=\frac{{{T}’}}{T}=\frac{3000}{2000}=\frac{3}{2} $