Transmission Of Heat Question 276

Question: The absolute temperatures of two black bodies are 2000 K and 3000 K respectively. The ratio of wavelengths corresponding to maximum emission of radiation by them will be

[RPMT 2003]

Options:

A) 2 : 3

B) 3 : 2

C) 9 : 4

D) 4 : 9

Show Answer

Answer:

Correct Answer: B

Solution:

$ {\lambda _{m}}T={{{\lambda }’} _{m}}{T}’ $

Therefore $ \frac{{\lambda _{m}}}{{{{{\lambda }’}} _{m}}}=\frac{{{T}’}}{T}=\frac{3000}{2000}=\frac{3}{2} $