Transmission Of Heat Question 300
Question: The ratio of radiant energies radiated per unit surface area by two bodies is 16 : 1, the temperature of hotter body is 1000K, then the temperature of colder body will be
Options:
A) 250 K
B) 500 K
C) 1000 K
D) 62.5 K
Show Answer
Answer:
Correct Answer: B
Solution:
$ Q\propto T^{4} $
$ \Rightarrow $ $ \frac{Q _{1}}{Q _{2}}=\frac{T _{1}^{4}}{T _{2}^{4}} $
$ \Rightarrow $ $ T _{2}^{4}=( \frac{E _{2}}{E _{1}} )T _{1}^{4} $
$ \Rightarrow $ $ T _{2}^{4}=\frac{1}{16}\times {{(1000)}^{4}}={{( \frac{1000}{2} )}^{4}} $
$ \Rightarrow $ $ T _{2}=500K $
BETA
