Transmission Of Heat Question 301
Question: In Newton’s experiment of cooling, the water equivalent of two similar calorimeters is 10 gm each. They are filled with 350 gm of water and 300 gm of a liquid (equal volumes) separately. The time taken by water and liquid to cool from $ 70^{o}C $ to $ 60^{o}C $ is 3 min and 95 sec respectively. The specific heat of the liquid will be
Options:
A) $ 0.3,Cal\text{/}gm\times {}^\circ C $
B) $ 0.6,Cal\text{/}gm\times {}^\circ C $
C) $ 0.6,Cal\text{/}gm\times {}^\circ C $
D) $ 0.8,Cal\text{/}gm\times {}^\circ C $
Show Answer
Answer:
Correct Answer: C
Solution:
$ S _{l}=\frac{1}{m _{l}}[ \frac{t _{l}}{t _{W}}(m _{W}C _{W}+W)-W ] $
$ =\frac{1}{300}[ \frac{95}{3\times 60}(350\times 1+10)-10 ] $
$ =0.6,Cal\text{/}gm\times {}^\circ C $
BETA
