Transmission Of Heat Question 35
Question: The thermal conductivity of a material in CGS system is 0.4. In steady state, the rate of flow of heat 10 cal/sec-cm2, then the thermal gradient will be
[MP PMT 1989]
Options:
A) $ 10{}^\circ C/cm $
B) $ 12{}^\circ C/cm $
C) $ 25{}^\circ C/cm $
D) $ 20{}^\circ C/cm $
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Answer:
Correct Answer: C
Solution:
$ \frac{\Delta Q}{\Delta t}=\frac{KA,\Delta \theta }{\Delta x} $
Therefore Thermal gradient $ \frac{\Delta \theta }{\Delta x} $
$ =\frac{(\Delta Q/\Delta t)}{K}=\frac{10}{0.4}=25{}^\circ C/cm $
BETA
