Transmission Of Heat Question 41
Question: The thickness of a metallic plate is 0.4 cm. The temperature between its two surfaces is $ 20^{o}C $ . The quantity of heat flowing per second is 50 calories from $ 5cm^{2} $ area. In CGS system, the coefficient of thermal conductivity will be
Options:
A) 0.4
B) 0.6
C) 0.2
D) 0.5
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{Q}{t}=\frac{KA(\Delta \theta )}{l} $
Therefore $ 50=\frac{5\times 20\ K}{0.4}\Rightarrow K=\frac{1}{5}=0.2 $
BETA
