Transmission Of Heat Question 64
Question: A heat flux of $ 4000\ J/s $ is to be passed through a copper rod of length $ 10\ cm $ and area of cross-section $ 100\ cm^{2} $ . The thermal conductivity of copper is $ 400\ W/m{{\ }^{o}}C $ . The two ends of this rod must be kept at a temperature difference of
[MP PMT 1999]
Options:
A) $ 1^{o}C $
B) $ 10^{o}C $
C) $ 100^{o}C $
D) $ 1000^{o}C $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \Delta \theta =\frac{Q\times l}{KAt}=\frac{4000\times 0.1}{400\times {{10}^{-2}}}=100^{o}C $
BETA
