[CPMT 1990]
A) $ 30{}^\circ $
B) $ 45{}^\circ $
C) $ 60{}^\circ $
D) $ 90{}^\circ $
Correct Answer: B $ |\vec{A}\times \vec{B}|,=\vec{A}|\vec{B}|\sin\theta$ Therefore $ AB\sin \theta = AB\cos \theta $ Therefore $ \tan \theta =1 $ \quad $ \theta =45{}^\circ $
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