Vectors Question 17
Question: The sum of two forces acting at a point is 16 N. If the resultant force is 8 N and its direction is perpendicular to minimum force then the forces are
[CPMT 1997]
Options:
A) 6 N and 10 N
B) 8 N and 8 N
C) 4 N and 12 N
D) 2 N and 14 N
Correct Answer: A $ A+B=16 $ (given) ?(i) $ \tan \alpha =\frac{B\sin \theta }{A+B\cos \theta }=\tan 90{}^\circ $ \ $ A+B\cos \theta =0 $ Therefore $ \cos \theta =\frac{-A}{B} $ ?(ii) $ 8=\sqrt{A^{2}+B^{2}+2AB\cos \theta } $ ?(iii) By solving eq. (i), (ii) and (iii) we get $ A=6N, $ $ B=10N $
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Answer:
Solution:
BETA
