Vectors Question 174
Question: A force $ \vec{F}=(5\hat{i}+3\hat{j})\ N $ is applied over a particle which displaces it from its original position to the point $ \vec{s}=(2\hat{i}-1\hat{j}) $ m. The work done on the particle is
[BHU 2001]
Options:
A) 12
B) 6
C) 1
D) 0
Correct Answer: A $ W=\overrightarrow{F}.\overrightarrow{s}=(3\hat{i}+c\hat{j}+2\hat{k}).(-4\hat{i}+2\hat{j}-3\hat{k}) $ $ W = -12 + 2c - 6 $ Work done $ W = 6J $ (given)
$ \ Therefore $ -12+2c-6=6 $
$ \Rightarrow $ $ c=3.00\times10^8 , \text{m/s} $
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Solution:
BETA
