Vectors Question 191
Question: A particle moves along a path ABCD as shown in the figure. Then the magnitude of net displacement of the particle from position A to D is:
Options:
A) 10 m
B) $ 5\sqrt{2},m $
C) 9 m
D) $ 7\sqrt{2},m $
Correct Answer: D [d] As seen from the figure the displacement is $ \sqrt{{{(AF)}^{2}}+{{(FD)}^{2}}}=7\sqrt{2},m $ .
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Answer:
Solution:
BETA
