Vectors Question 199
Question: At what angle should the two forces 2P and $ \sqrt{2},P $ act so that the resultant force is $ P\sqrt{10},? $
Options:
A) $ 45{}^\circ $
B) $ 60^{o} $
C) $ 90^{o} $
D) $ 120^{o} $
Correct Answer: A [a] $ P\sqrt{10}=,\sqrt{4P^{2}+,2P^{2}+4\sqrt{2}P^{2},\cos \theta } $ Therefore $ \theta =,45^{\circ} $
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Solution:
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BETA
