Wave Mechanics Question 591
Question: A cylindrical block of wood (density = 650 kg $ {{m}^{-3}} $ ), of base area 30cm2 and height 54 cm, floats in a liquid of density 900 kg $ {{m}^{-3}} $ . The block is depressed slightly and then released. The time period of the resulting oscillations of the block would be equal to that of a simple pendulum of length (nearly)
Options:
A) 52cm
B) 65cm
C) 39cm
D) 26cm
Show Answer
Answer:
Correct Answer: C
Solution:
[c] h = Length of block immerged in water $ mg=F _{B} $
$ \rho A\lg ={\rho _{B}}Ahg $
$ 650\times A\times 54\times {{10}^{-2}}g=900\times A\times hg $
$ \Rightarrow ,h=0.39m=39m. $
BETA
