Wave Mechanics Question 601
Question: A forced oscillator is acted upon by a force $ F=F _{0} $ sin cot. The amplitude of oscillation is given by $ \frac{55}{\sqrt{2{{\omega }^{2}}-36\omega +9}} $ . The resonant angular frequency is
Options:
A) 2 unit
B) 9 unit
C) 18 unit
D) 36 unit
Show Answer
Answer:
Correct Answer: B
Solution:
[b] At resonance, amplitude of oscillation is maximum
$ \Rightarrow 2{{\omega }^{2}}-36\omega +9isminimum $
$ \Rightarrow ,4\omega -36=0 $ (derivative is zero)
$ \Rightarrow ,\omega =9 $
BETA
