Wave Mechanics Question 610
Question: The time period of simple pendulum of length 1m suspended in a car that is moving with constant speed 36 km/hr around a circle of radius 10mis:
Options:
A) $ \pi \sqrt{2}\sec $
B) $ \frac{\pi }{10}\sqrt{2}\sec $
C) $ \frac{\pi }{10\sqrt{2}}\sec $
D) $ \frac{5\pi }{\sqrt{2}}\sec $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Given, $ V=36\times \frac{5}{18}m/s=10/s $ , $ g=10m/s^{2},,r=10m,,l=1m $
$ T=2\pi \sqrt{\frac{\ell }{g^{2}+{{( \frac{v^{2}}{r} )}^{2}}}}=2\pi \sqrt{\frac{1}{10^{2}+{{( \frac{100}{10} )}^{2}}}} $
$ =\frac{\pi }{10}\sqrt{2}\sec $
BETA
