Wave Mechanics Question 620
Question: Two waves are represented by the equations $ y _{1}=a\sin (\omega t+kx+0.57)m $ and $ y _{2}=a\cos $ $ (\omega t+kx)m $ , where x is in meter and t in sec. The phase difference between them is
Options:
A) 1.0 radian
B) 1.25 radian
C) 1.57 radian
D) 0.57 radian
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Here, $ y _{1}=a,\sin ,(\omega t+kx+0.57) $ and $ y _{2}=a,\cos ,(\omega t+kx) $
$ =a,\sin [ \frac{\pi }{2}+(\omega t+kx) ] $ Phase difference, $ \Delta \phi ={\phi _{2}}={\phi _{1}} $
$ =\frac{\pi }{2}-0.57 $
$ =\frac{3.14}{2}-0.57=1.57-0.57=1,radian $
BETA
