Wave Mechanics Question 624
Question: At t=0, the shape of a travelling pulse is given by $ y(x,0)=\frac{4\times {{10}^{-3}}}{8\times {{(x)}^{-2}}} $ where x and y are in metres. The wave function for the travelling pulse if the velocity or propagation is 5 m/s in the x direction is given by
Options:
A) $ y(x,t)=\frac{4\times {{10}^{-3}}}{8-(x^{2}-5t)} $
B) $ y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x-5t)}^{2}}} $
C) $ y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x+5t)}^{2}}} $
D) $ y(x,t)=\frac{4\times {{10}^{-3}}}{8-(x^{2}+5t)} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ y(x,t)=f(x-vt) $
$ y=(x,0)=\frac{4\times {{10}^{-3}}}{8-x^{2}} $ For a travelling wave in the x-direction $ y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x-5t)}^{2}}} $
BETA
