Wave Mechanics Question 652
Question: Length of a sonometer wire between two fixed ends is 110 cm. If the fundamental frequencies are in the ratio of 1: 2: 3, then what is the ratio of lengths of these segments of the wire?
Options:
A) 3 : 2 : 1
B) 6 : 3 : 2
C) 6 : 2 : 3
D) 2 : 3 : 6
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Frequency $ v=\frac{1}{2L}\sqrt{\frac{T}{m}} $
$ \because V\propto \frac{1}{l} $
$ \
Therefore l _{1}:l _{2}:l _{3}=\frac{1}{1}:\frac{1}{2}:\frac{1}{3}=6:3:2 $
BETA
