Wave Mechanics Question 660
Question: In a standing wave formed as a result of reflection from a surface, the ratio of the amplitude at an antinode to that at node is x. The fraction of energy that is reflected is
Options:
A) $ {{[ \frac{x-1}{x} ]}^{2}} $
B) $ {{[ \frac{x}{x+1} ]}^{2}} $
C) $ {{[ \frac{x-1}{x+1} ]}^{2}} $
D) $ {{[ \frac{1}{x} ]}^{2}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ \frac{A _{1}+A _{2}}{A _{1}-A _{2}}=x;\frac{A _{2}}{A _{1}}=\frac{x-1}{x+1};,Energy\propto A^{2} $
$ \Rightarrow {{( \frac{x-1}{x+1} )}^{2}} $
BETA
