Wave Mechanics Question 524
Question: Two parallel and opposite forces, each of magnitude 4000 N are applied tangentially to the upper and lower faces of a cubical metal block 25 cm on a side. The angle of Shear is
[shear modulas of metal is 80 G Pa]
Options:
A) $ 8\times {{10}^{-7}}rad $
B) $ 7\times {{10}^{-7}}rad $
C) $ 6\times {{10}^{-6}}rad $
D) $ 5\times {{10}^{-5}}ra $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] Shear stress $ =\frac{F}{A} $
$ \tan \theta =\frac{shear,stress}{shear,\bmod ulus} $
$ \Rightarrow \tan \theta =\frac{4000}{{{(0.25)}^{2}}\times 8\times 10^{10}} $
$ \tan \theta =8\times {{10}^{-7}} $ for small angle $ \tan \theta =\theta =8\times {{10}^{-7}}rad $
BETA
