[MP PET 1984; CBSE PMT 1993; AFMC 1996; RPET 2002]
A) l
B) $ \frac{\lambda }{2} $
C) $ \frac{\lambda }{4} $
D) 2l
Correct Answer: C
The distance between the nearest node and antinode in a stationary wave is $ \frac{\lambda }{4} $
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