Wave Mechanics Question 695
Question: The phase difference between the two particles situated on both the sides of a node is
[MP PET 2002]
Options:
A) 0°
B) 90°
C) 180°
D) 360°
Show Answer
Answer:
Correct Answer: C
Solution:
Both the sides of a node, two antinodes are present with separation $ \frac{\lambda }{2} $ So phase difference between then $ \varphi =\frac{2\pi }{\lambda }\times \frac{\lambda }{2}=\pi $
BETA
