Wave Mechanics Question 697
Question: For the stationary wave $ y=4\sin ,( \frac{\pi x}{15} )\cos (96,\pi t) $ , the distance between a node and the next antinode is
[MP PMT 1987]
Options:
A) 7.5
B) 15
C) 22.5
D) 30
Show Answer
Answer:
Correct Answer: A
Solution:
Comparing given equation with standard equation $ y=2a\sin \frac{2\pi x}{\lambda }\cos \frac{2\pi vt}{\lambda } $ gives us $ \frac{2\pi }{\lambda }=\frac{\pi }{15}\Rightarrow \lambda =30 $ Distance between nearest node and antinodes = $ \frac{\lambda }{4}=\frac{30}{4}=7.5 $
BETA
