Wave Mechanics Question 698
Question: The equation of stationary wave along a stretched string is given by $ y=5\sin \frac{\pi x}{3}\cos 40\pi t $ , where x and y are in cm and t in second. The separation between two adjacent nodes is
[CPMT 1990; MP PET 1999; AMU 1999; DPMT 2004; BHU 2005]
Options:
A) 1.5 cm
B) 3 cm
C) 6 cm
D) 4 cm
Show Answer
Answer:
Correct Answer: B
Solution:
On comparing the given equation with standard equation $ y=2a\sin \frac{2\pi x}{\lambda }\cos \frac{2\pi vt}{\lambda } $
Therefore $ \frac{2\pi x}{\lambda }=\frac{\pi x}{3}\Rightarrow \lambda =6 $ Separation between two adjacent nodes = $ \frac{\lambda }{2}=3 $ cm
BETA
