Wave Mechanics Question 70
Question: A man stands in front of a hillock and fires a gun. He hears an echo after 1.5 sec. The distance of the hillock from the man is (velocity of sound in air is 330 m/s)
[EAMCET (Eng.) 1998; CPMT 2000]
Options:
A) 220 m
B) 247.5 m
C) 268.5 m
D) 292.5 m
Show Answer
Answer:
Correct Answer: B
Solution:
If d is the distance between man and reflecting surface of sound then for hearing echo $ 2d=v\times t\Rightarrow d=\frac{330\times 1.5}{2}=247.5 $
$ m $
BETA
