Wave Mechanics Question 724
Question: Standing waves are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s, the frequency is
[CBSE PMT 1997; AIIMS 1998; JIPMER 2000]
Options:
A) 2 Hz
B) 4 Hz
C) 5 Hz
D) 10 Hz
Show Answer
Answer:
Correct Answer: C
Solution:
String vibrates in five segment so $ \frac{5}{2}\lambda =l $
Therefore $ \lambda =\frac{2l}{5} $ Hence $ n=\frac{v}{\lambda }=5\times \frac{v}{2l} $
$ =5\times \frac{20}{2\times 10}=5 $
$ Hz $
BETA
