Wave Mechanics Question 725

Question: The velocity of waves in a string fixed at both ends is 2 m/s. The string forms standing waves with nodes 5.0 cm apart. The frequency of vibration of the string in Hz is

[SCRA 1998]

Options:

A) 40

B) 30

C) 20

D) 10

Show Answer

Answer:

Correct Answer: C

Solution:

Here $ \frac{\lambda }{2}=5.0,cm $
$ \Rightarrow \lambda =10 $

$ cm $ Hence $ n=\frac{v}{\lambda }=\frac{200}{10}=20 $ Hz.