Wave Mechanics Question 76
Question: The temperature at which the speed of sound in air becomes double of its value at $ 0^{o}C $ is
[AIEEE 2002]
Options:
A) 273K
B) 546K
C) 1092K
D) 0K
Show Answer
Answer:
Correct Answer: C
Solution:
$ v\propto \sqrt{T} $
Therefore $ \sqrt{\frac{T _{2}}{T _{1}}}=\frac{v _{2}}{v _{1}}\Rightarrow T _{2}=T _{1}{{( \frac{v _{2}}{v _{1}} )}^{2}} $
$ \Rightarrow T _{2}=273\times 4=1092K $
BETA
