Wave Mechanics Question 769
Question: A string of length 2 m is fixed at both ends. If this string vibrates in its fourth normal mode with a frequency of 500 Hz then the waves would travel on its with a velocity of
[BCECE 2005]
Options:
A) 125 m/s
B) 250 m/s
C) 500 m/s
D) 1000 m/s
Show Answer
Answer:
Correct Answer: C
Solution:
For string $ \lambda =\frac{2l}{p} $ where p = No. of loops = Order of vibration Hence for forth mode p = 4
Therefore $ \lambda =\frac{l}{2} $ Hence v = nl $ =500\times \frac{2}{2}=500,Hz $
BETA
