Wave Mechanics Question 79
Find the frequency of minimum distance between compression & rarefaction in a wire. If the length of the wire is 1m & velocity of sound in air is 360 m/s
[CPMT 2003]
Options:
A) 90 sec?1
B) 180s?180
C) 120 sec?1
D) 360 sec?1
Show Answer
Answer:
Correct Answer: A
Solution:
The minimum distance between compression and rarefaction of the wire $ l=\frac{\lambda }{4} $
$ \
Therefore $ Wave length $ \lambda =4l $ Now by $ v=n\lambda \Rightarrow n=\frac{v}{4\times 1}=90 $
$ {{\sec}^{-1}}. $
BETA
