Wave Mechanics Question 821
Question: If velocity of sound in a gas is 360 m/s and the distance between a compression and the nearest rarefaction is 1m, then the frequency of sound is
[KCET 1999]
Options:
A) 90 Hz
B) 180 Hz
C) 360 Hz
D) 720 Hz
Show Answer
Answer:
Correct Answer: B
Solution:
Distance between a compression and the nearest rarefaction is $ \frac{\lambda }{2}=1m,. $ Hence $ n=\frac{v}{\lambda }=\frac{360}{2}=180,Hz $ .
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