Wave Mechanics Question 827
Question: A man sets his watch by the sound of a siren placed at a distance 1 km away. If the velocity of sound is 330 m/s
[JIPMER 1999]
Options:
A) His watch is set 3 sec. faster
B) His watch is set 3 sec. slower
C) His watch is set correctly
D) None of the above
Show Answer
Answer:
Correct Answer: B
Solution:
$ \text{Time}=\frac{\text{Distance }}{\text{Velocity}}=\frac{1000}{330}=3.03 $
$ \sec $ . Sound will be heard after 3.03 sec. So his watch is set 3sec, slower.
BETA
