Wave Mechanics Question 54
Question: The phase difference between two points separated by 1m in a wave of frequency 120 Hz is $ 90^{o} $ . The wave velocity is
[KCET 1999]
Options:
A) 180 m/s
B) 240 m/s
C) 480 m/s
D) 720 m/s
Show Answer
Answer:
Correct Answer: C
Solution:
Path difference $ \Delta =\frac{\lambda }{2\pi }\times \varphi $
Therefore $ 1=\frac{\lambda }{2\pi }\times \frac{\pi }{2} $
Therefore l = 4m Hence $ v=n\lambda $ = $ 120\times 4=480 $
$ m/s $
BETA
