Wave Mechanics Question 541
Question: When the displacement of a particle executing simple harmonic motion is half of its amplitude, the ratio of its kinetic energy to potential energy
Options:
A) 1 : 3
B) 2 : 1
C) 3 : 1
D) 1 : 2
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Given, $ x=\frac{A}{2} $
$ \
Therefore from,x=A,\sin ,\omega t\Rightarrow \omega t=30^{o} $ And, $ \frac{KE}{PE}={{\cot }^{2}}\omega t={{(\sqrt{3})}^{2}}=3 $
BETA
